awk 或sed 问题

共有 6 条评论

1. shell_master 于 2011-11-26 17:06:06发表:

   没有解决?

2. irwin520 于 2011-11-17 09:35:39发表:

   引用:

   第一个
   cat filename|awk -v RS= -F "\n" '{for(i=1;$i != "";i++){split($i,x,"=");if(length(x[1])>max){max=length(x[1])}};m=max"";for(i=1;$i != "";i++){split($i,x,"=");printf "\"%" m "s=%s\"",x[1],x[2]; ...
   tim211314 发表于 2011-10-28 20:32

   
   
   
   我测试了 好像没有对齐，结果如下：
   
   [irwin@IRWIN test]$ cat net1|awk -v RS= -F "\n" '{for(i=1;$i != "";i++){split($i,x,"=");if(length(x[1])>max){max=length(x[1])}};m=max"";for(i=1;$i != "";i++){split($i,x,"=");printf "\"%" m "s=%s\"",x[1],x[2];printf "\n"}}'|sed 's/"//g'
   chown = CHange OWNer
   chsh = CHange SHell
   cmp = compare
   cobra = Common Object Request Broker Architecture
   comm = common
   cp = CoPy
   cpio = CoPy In and O
   文件如下：
   [irwin@IRWIN test]$ cat net1
   chown = CHange OWNer
   chsh = CHange SHell
   cmp = compare
   cobra = Common Object Request Broker Architecture
   comm = common
   cp = CoPy
   cpio = CoPy In and O
   [irwin@IRWIN test]$
   
   
   
   

3. irwin520 于 2011-11-17 09:29:54发表:

   2# ICEEN
   
   
   这个好像也不能实现吧。

4. tim211314 于 2011-10-28 20:32:39发表:

   第一个
   cat filename|awk -v RS= -F "\n" '{for(i=1;$i != "";i++){split($i,x,"=");if(length(x[1])>max){max=length(x[1])}};m=max"";for(i=1;$i != "";i++){split($i,x,"=");printf "\"%" m "s=%s\"",x[1],x[2];printf "\n"}}'|sed 's/"//g'

5. 书中、颜如玉 于 2011-09-27 15:36:36发表:

   awk? 截取？

6. ICEEN 于 2011-09-05 22:37:23发表:

   前一个已解决 sed 's/[[:space:]]=/\t=/g'